Khi giải phương trình \(\dfrac{3\left(x+1\right)+1}{4}-1=\dfrac{3x+2}{2}+\dfrac{4x+5}{5}\) , ta được nghiệm là
\(x=-\frac{40}{31}\).\(x=\frac{40}{31}\).\(x=-1\).\(x=-\frac{31}{30}\).Hướng dẫn giải:\(\dfrac{3\left(x+1\right)+1}{4}-1=\dfrac{3x+2}{2}+\dfrac{4x+5}{5}\)
\(\Leftrightarrow\dfrac{5\left(3x+4\right)}{20}-\dfrac{20}{20}=\dfrac{10\left(3x+2\right)}{20}+\dfrac{4\left(4x+5\right)}{20}\)
\(\Leftrightarrow5\left(3x+4\right)-20=10\left(3x+2\right)+4\left(4x+5\right)\)
\(\Leftrightarrow15x+20-20=30x+20+16x+20\)
\(\Leftrightarrow-31x=40\)
\(\Leftrightarrow x=-\frac{40}{31}\)
