\(x\left(x+4\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x+4=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=0-4\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-4\end{matrix}\right.\)
Vậy \(x\in\left\{0;-4\right\}\)
|x-3| + |y-2x | =0
|x| + 3|2x -x ² | =0
|5x ² -5 | + 4|y-7 | =0
||x +1 | + |y-5 |=0
|x ² -1| + |y-1| =0
|x-1 | +|x ²-x |=0
tim x
a)x-5/x-3 >0
b)x+8/x-9<0
c) (x+1)/2017 +(x+2)/2016 +(x+3)/2015 +(x+4)/2014 +4=0
tìm x biết:
x2-3x=0
x(x-2)<0
(x+1)(x+4)>0
Tìm x:
A, (x-3)(x-2)<0
B, (2x-1)(x-2)<0
C, (x+3)(x-4)>0
D, x^2(x+1)> hoặc bằng 0
E, (3x+1)(x-2)(x^2+1)>0
Tìm x;y;z
A. x:y:z=2:3:4 và x +y+z=365
B. |x-(9/2)|+|y+(4/3)|+ |(7/2)+z|=0
C. [(1/2)×x-5]20+[y^2-(1/4)|=0
D.x^2+[y-(1/10]^4=0
Tìm x biết:
A, (x+3)(x-2)<0
B, (2x-1)(x-2)<0
C, (x+3)(x-4)>0
D, x^2 (x+1)> hoặc = 0
E, (3x+1)(x-2)(x^2+1)>0
TÌm x thuộc z để
a)(2x-1).(x+5)>0
b)(x^2-2).(x^2-3).(x^2-1)<0
c)(x-1).(x-2).(x-3).(x-4)>0
(x+1) (3-2x) >0
(x-3) (6-x) <o
(2x+4) (5-x) >0
tìm các số nguyên x, biết :
a, x . ( 8-x ) < 0
b, ( 2-x ) . ( x+3 ) > 0
c, ( 2x-4 ) . ( 5-x ) < 0
Tìm x biết:
a, 5x+2>3x-1
b, \(\dfrac{3}{4}.x-\dfrac{1}{2}>\dfrac{1}{2}.x+\dfrac{3}{4}\)
c, (x-2).(x-3)>0
d, (2x+4)(x-5)<0
