Ta có :
\(n_{O_2}=\dfrac{m_{O_2}}{M_{O_2}}=\dfrac{6,4}{32}=0,2\left(mol\right)\\ n_{H_2}=\dfrac{m_{H_2}}{M_{H_2}}=\dfrac{0,6}{2}=0,3\left(mol\right)\)
\(\Rightarrow\overline{M}_{hh}=\dfrac{m_{O_2}+m_{H_2}}{n_{O_2}+n_{H_2}}=\dfrac{6,4+0,6}{0,2+0,3}=14\left(g/mol\right)\)
\(\Rightarrow d_{hh/N_2}=\dfrac{\overline{M}_{hh}}{M_{N_2}}=\dfrac{14}{14}=1\)
===> Vậy ...
Ta có :
\(n_{O_2}=\dfrac{m_{O_2}}{M_{O_2}}=\dfrac{6,4}{32}=0,2\left(mol\right)\\ n_{H_2}=\dfrac{m_{H_2}}{M_{H_2}}=\dfrac{0,6}{2}=0,3\left(mol\right)\)
\(\Rightarrow\overline{M}_{hh}=\dfrac{m_O_{_2}+m_{H_2}}{n_{O_2}+n_{H_2}}\\ =\dfrac{6.4+0.6}{0.2+0.3}=\dfrac{7}{0.5}=14\left(g/mol\right)\)\(\Rightarrow d_{hh/N_2}=\dfrac{\overline{M}_{hh}}{M_{N_2}}=\dfrac{14}{28}=\dfrac{1}{2}=0,5\)
