Question

x+5/2005+x+6/2004+x+7/2003=-3 tìm x, mọi người giải giúp mình với nhanh giừm mình

Answer 1

Giải:

\(\dfrac{x+5}{2005}+\dfrac{x+6}{2004}+\dfrac{x+7}{2003}=-3\)

\(\Leftrightarrow\dfrac{x+5}{2005}+\dfrac{x+6}{2004}+\dfrac{x+7}{2003}+3=0\)

\(\Leftrightarrow\dfrac{x+5}{2005}+1+\dfrac{x+6}{2004}+1+\dfrac{x+7}{2003}+1=0\)

\(\Leftrightarrow\dfrac{x+5+2005}{2005}+\dfrac{x+6+2004}{2004}+\dfrac{x+7+2003}{2003}=0\)

\(\Leftrightarrow\dfrac{x+2010}{2005}+\dfrac{x+2010}{2004}+\dfrac{x+2010}{2003}=0\)

\(\Leftrightarrow\left(x+2010\right)\left(\dfrac{1}{2005}+\dfrac{1}{2004}+\dfrac{1}{2003}\right)=0\)

\(\Leftrightarrow x+2010=0\)

\(\Leftrightarrow x=-2010\)

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