\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)-27=0\)
\(\Leftrightarrow x^3+27-x\left(x^2-1\right)-27=0\)
\(\Leftrightarrow x^3+27-x^3+x-27=0\)
\(\Leftrightarrow x=0\)
Vậy \(x=0.\)
\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)-27=0\)
\(\Leftrightarrow x^3+27-x\left(x^2-1\right)-27=0\)
\(\Leftrightarrow x^3+27-x^3+x-27=0\)
\(\Leftrightarrow x=0\)
Vậy \(x=0.\)
Tìm x :
a/2x(x - 1) - x(4 - x) = 0
b/3(1 - 4x)(x - 1) + 4(3x - 2)(x + 3)=-27
Tìm x bt
1) 3.(2x−1).(3x−1)−(2x−3).(9x−1)−3=−3
2) 3x−1.(2x+7)−x+1.(6x−5)=x+2−(x−5)
3) 3xy.(x+y)−(x+y).(x2+y2+2xy)+y3=27
4) 5.x+1.(1−x).(2x2+3)=0
giúp mk vs mai mk đi hk rù
Tìm x bt
1) 3.(2x−1).(3x−1)−(2x−3).(9x−1)−3=−3−3
2) 3x−1.(2x+7)−x+1.(6x−5)=x+2−(x−5)
3) 3xy.(x+y)−(x+y).(x2+y2+2xy)+y3=27
4) 5.x+1.(1−x).(2x2+3)=0
giúp mk vs mai mk đi hk rùi
a. 3[x^2 - 2x +1]+x[2-3x]=7
b. 5[x-2] +2[x+3]=10
c. [x+1][-3]+5[x-4]=-3
d. 2[x-1]-x[3-x]=x^2
đ. 3x[x+5]-2[x+5]=3x^2
e. 4x[x+2]+x[4-x]=3x^2 +12
f. 1/3x [3x+6]-x[x-5]=9
(x+1)(x+2)-(x+3)(x2-3x+9)
x2 -6x+4y2+4y+10=0
152+852+170.45
đáp án của các câu sau : tìm x
a ) ( 3x-1 ) ( 2x+7 ) - ( x+1 )(6x-5)=16
b ) ( 10x+9)x-(5x-1 )(2x+3 )=8
c ) ( 3x -5 ) ( 7-5x ) + ( 5x+2 ) (3x-2 ) -2 = 0
d ( x+1)x(x+6)-\(^{x^3}\)=5x [ câu này giải luôn hộ mk nha ]
27+(x - 3)(x+3x+9) với x=-3
em gấp ạ
16 Tìm x, biết
a) 4(x+2)-7(2x-1)+9(3x-4)=30 ; b) 2(5x-8)-3(4x-5)=4(3x-4)+11
c) 5x(1-2x)-10(x+8)=0 ; d) (5x-3).4x-2x.(10x-3)=15
Tìm x, biết:
a, (x+8).(x+6)-x^2=104
b, (x+1).(x+2)-(x-3).(x+4)=6
c, 3.(2x-1).(x+2)-2.(3x+2).(x-4)=5