Question

\(x(2x-9)=3x(x-5)\)

Answer 1

`x(2x-9)=3x(x-5)`

`<=>2x^2-9x=3x^2-15x`

`<=>-x^2+6x=0`

`<=>-x(x-6)=0`

`<=>` \(\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)

Vậy `S={0;6}`.

Answer 2

 \(x\left(2x-9\right)=3x\left(x-5\right)\)

<=> \(2x^2-9x=3x^2-15x\)

<=> \(-x^2+6x=0\)

<=> \(-x\left(x-6\right)=0\)

=> x=0 hoặc \(x-6=0=>x=6\)