\(\left|x\right|+2=5\\ \Leftrightarrow\left|x\right|=3\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy \(x=3\) hoặc \(x=-3\) là giá trị cần tìm
Tìm x, biết:
a) ( x - 5)(x + 5) - ( x- 3)2 + 3( x - 2)2 = ( x + 1)2 - ( x+4)( x - 4) + 3x2
b) ( 2x + 3)2 + ( x - 1)( x + 1) = 5( x + 2)2 - ( x - 5)( x + 1) + ( x + 4)2
rút gọn biểu thức
a 4x2 - (x+3)(x-5)+x
b x (x-5) - 3x (x+1)
c 4x (x2 -x -1)-(x2-2) (x+3)
d (x +3) (x-1)-(x-7)(x-6)
tìm x?
a 4x (x-5)-(x-1)(4x-3)=5
b (3x-4)(x-2)=3x(x-9)-9
c (x-5)(x-1)=(x-1)(x-2)
chứng minh biểu thức sau không phục thuộc vào biến
A= (4x-5)(x+2)-(x+5)(x-3)-3x2-x
bài 1 :
a/ 4x^2-(x+3)(x-5)+x
b/ X(x-5)-3x(x+1)
c/(x-1)(x+2)-(x+5)(x-2)
d/ (-x-2)(x+1)-(x-5)(-x+1)
Tìm x
Bài 1
1.(x-3)(x+2)-x(x-7)=15
2.(x-5)(x+5)+x(3-x)=20
3.(x-7)2-x(2+x)=-7
4.(x-4)2-(x+4)(x-4)=-16
5.(x-5)(x+5)-x(2-3x)=4x2-7
Bai2
1.2x(x-2)+3x-6=0
2.3x(x-5)-5x+25=0
3.x(x+7)-x-7=0
4.(5x-20)+3x2-12x=0
5.(1-x)-3x2+3x=0
a) 4x(x-5)-7x(x-4)+3x2=12
b)-3x(x-5)+5(x-1)+3x2=4-x
c)(x-5)(x-4)-(x+1)(x-2)=7
d)-(x+3)(x-4)+(x-1)(x+1)=10
e)(x-3)(x2+3x+9)+x(5-x2)=6x
Tìm x biết:
a)(x+3)^2+(x-2)(x+2)-2(x+1)=7
b)x(2x-1)-(x-2)(2x+3)=0
c)(x-1)(x+2)-x-2=0
d)x[(3x+2)+(x+1)^2-(2x-5)(2x+5)]=0
đ) 2x^2-7x+5=0
e) (2x+3)(x-5)=(2x+1)(2×+3)
Tìm x :
a, (2x-5).(x+2)-2x.(x-1)=15
b, (5-2x).(2x+7)=4\(x^2\)-25
c, x.(4x-5)-(2x+1)\(^2\)=0
M.n giúp em với
19 Tìm x, biết
a) (x+2)(x+3)-(x-2)(x+5)=0 ; b) (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c) (8-4x)(x+2)+4(x-2)(x+1)=0 ; d) (2x-3)(8x+2)=(4x+1)(4x-1)-3
a) x2(x - 5) + 5 - x = 0; b) 3x4 - 9x3 = -9x2 + 27x;
c) x2(x + 8) + x2 = -8x; d) (x + 3)(x2 -3x + 5) = x2 + 3x.
e) 3x(x - 1) + x - 1 = 0;
f) (x - 2)(x2 + 2x + 7) + 2(x2 - 4) - 5(x - 2) = 0;
g) (2x - 1)2 - 25 = 0;
h) x3 + 27 + (x + 3)(x - 9) = 0.
i)8x3 - 50x = 0; k) 2(x + 3)-x2 - 3x = 0;
m)6x2 - 15x - (2x - 5)(2x + 5) =
