\(x^2+4x+4=x^2+2\cdot x\cdot2+2^2=\left(x+2\right)^2\)
\(x^2+4x+4\)
\(=x^2+2.x.2+2^2\)
\(=\left(x+2\right)^2\)
\(x^2+4x+4=x^2+2.x.2+2^2=\left(x+2\right)^2\)
\(x^2+4x+4=x^2+2\cdot x\cdot2+2^2=\left(x+2\right)^2\)
\(x^2+4x+4\)
\(=x^2+2.x.2+2^2\)
\(=\left(x+2\right)^2\)
\(x^2+4x+4=x^2+2.x.2+2^2=\left(x+2\right)^2\)
giải phương trình:
j) 3x2 +7x+2=0
k) x2 -4x+1=0
l) 2x2 - 6x +1=0
m) 3x2 +4x - 4=0
n) x6 - x2 =0
o) x3 -12 =13x
p) -x5 +4x4 = -12x3
q) x3 =4x
1. Giải các phương trình: a) 4x - 3 = 4 - 3x b) 3+ (x-5)=2(3x-2) c) 2(x-0,5)+3=0,25(4x-1) d) 2(x-\(\dfrac{1}{4}\) )-4=-6(\(\dfrac{-1}{3}\) x+0,5)+2
x2-4x+4=9
(x-7)(2x+5)=0
4x2-6x=0
4(3x-2)-3(x-4)=7x+10
2x(x+3)+5 (x+3)=0
2x (x-3)-5 ( x-3)=0
x3-6x2+5x=0
2(3-x)-(2x+5)=4x+3 3-2x/4-x+3/3=2
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
1. Giải các phương trình
b) 3+ (x-5)=2(3x-2) c) 2(x-0.5)+3=0.25(4x-1)
d) 2(x-\(\dfrac{1}{4}\))-4=-6(-\(\dfrac{1}{3}\)x+0.5)+2
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) = (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) = 2x(3x – 5)
3) (x – 2) 2 = (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) = 0
5) (x–2)(x –5) – (x–3)(x–4) = 0
6) (3x – 2)(4x + 3) = 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) = 0
8) (4x–5)(x+3) = (2x – 3)(7+2x)
9) (x + 3)(x – 2) = (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 = 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 = 2(x– 2)(x+2)
12) (x – 5) 2 = (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 = 5x + 38
Giải pt sau đây:
\(\frac{1}{x-2}-\frac{x^2-4x}{4-x^2}=0\)