Question

(X+2)(3x-24) - 12(8-x) = 0

Answer 1

⇔3x² -24x+6x-48-96+12x=0

⇔3x² -6x-144=0

⇔(x-8)(x+6)=0

⇔\(\left[{}\begin{matrix}x=8\\x=-6\end{matrix}\right.\)

Vậy S={8;-6}

Answer 2

\(\left(x+2\right)\left(3x-24\right)-12\left(8-x\right)=0\)

\(\Leftrightarrow3\left(x+2\right)\left(x-8\right)+12\left(x-8\right)=0\)

\(\Leftrightarrow\left(x-8\right)\left(3x+18\right)=0\)

\(TH_1:x-8=0\)

\(\Leftrightarrow x=8\)

\(TH_2:3x-18=0\)

\(\Leftrightarrow3\left(x-6\right)=0\)

\(\Leftrightarrow x-6=0\)

\(\Leftrightarrow x=6\)

Vậy pt có tập nghiệm \(S=\left\{6;8\right\}\)