\(\left(x+2\right)^2\) \(=\) \(x^2+2.x.2+2^2=x^2+4x+4\)
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Bài 3: Những hằng đẳng thức đáng nhớ
Các câu hỏi tương tự
Mn giúp mình bài này với:
B1:A=(x^2+3x+1)^2+(3x-1)^2+(3x-1)^2-2(x^2+3x+x+1)(3x-1)
B2:TÌm x:
a,2(x-1)^2+(x+3)^2=3(x-2)(x+1)
b,(x+2)^2-2(x-3)^2=(x+1)^2
c,(x-1)^2+(x-2)^2=2(x+4)^2-22x+7
Tìm x biết
a,(x+4)^2-(x+1)(x-1)=16
b,(2x-1)^2-(x+3)-5(x-7)(x+7)=0
c,3(x-1)^2-3x(x-5)=1
d,6(x-2)^2+(5x-2)^2-4(3x-1)(5x-2)=0
e,(x-2)^3-x^2(x-6)=4
g,(x-1)(x^2+x+1)-x(x+2)(x-2)=5
h,(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Rút gọn
1 (x-2)^2 + (x+3)^2-2.(x+1).(x-1)
2 ( x-y).(x+y).(x^2 +y^2).(x^4 + y^4)
3 3.(x-y)^2-2(x+y)^2+(x+y).(x-y)
4 (x-1)^2 -2(x-1)(x-3)+(x-3)^2
\(1, (-x+5)(x-2)+(x-7)(x+7)=(3x+1)^2-(3x-2)(3x+2)\)
\(2, (5x-1)(x+1)-2(x-3)^2=(x+2)(3x-1)-(x+4)^2+(x^2-x)\)
3, \((x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2 +(x-2)^2-x^2\)
(x^2+x+2)^2+(x-1)^2-2(x^2+x+2)(x-1)
1, tìm x :
a) (x+2).(x+3)-(x-2).(x+5)=0
b) (2x+3).(x-4)+(x-5).(x-2)=(x-4).(3x-5)
c) (3x-5).(7-5x)-(5x+2).(2-3x)=3
d)(x-7).(x+7)-(x-4)2-x=10+3
e) (x+1/2)2-(x-1).(x+1)=2x-1
2, Thu gọn :
a) (x+5)2-(3-x)2-2(x-4).(x+4)
b)4(x-1)2+(2x+3)2-8(x-2)(x+2)
21 tháng 7 2017 lúc 15:59
rút gọn biểu thức
a.(x^2-2x+2)(x-2)(x^2+2x+2)(x+2)
b.(x+1)^3+(x-1)^3+x^3-3x(x+1)(x-1)
c.(x+y+z)^2+(x+y-z)^2+(2x-y)^2
d.100^2-99^2+98^2-97^2+...+2^2-1^2
(x+2)^2-2x(x+1)+(x-3)(x+3)
(x+2y)(x^2-2xy+4y^2)-(x-2y)(x^2+2xy+4y^2)+2y^3
(3+x)(x^2-9)-(x-3)(x^2+3x+9)
(x-y)^3-(x-y)(x^2+xy+y^2)
Tìm x, biết :
a, ( x-3)^3 - ( x-3) ( x^2 + 3x+9) + 9( x+1)^2 = 15
b, 4x^2 - 81 = 0
c, x(x-5) ( x+5) - ( x-2) ( x^2 + 2x + 4 ) = 3
d, 25x^2 - 2 = 0
e, ( x+2)^2 = ( 2x-1)^2
f, ( x+2)^2 - x+4 = 0
2 tháng 10 2020 lúc 18:48
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+2)(x^2-2x+4)-x(x^2+2)=15
c)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
d)(x^2-1)^3-(x^4+x^2+1)(x^2-1)=0