Question

x2-7x+6. giai ho em voi

Answer 1

\(x^2-7x+6=0\)

\(\Leftrightarrow x^2-6x-x+6=0\)

\(\Leftrightarrow\left(x^2-6x\right)-\left(x-6\right)=0\)

\(\Leftrightarrow x\left(x-6\right)-\left(x-6\right)\)

\(\Leftrightarrow\left(x-1\right)\left(x-6\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=6\end{matrix}\right.\)

Answer 2

x\(^2\)-7x+6=0

\(\Leftrightarrow\)x\(^2\)-x-6x+6=0

\(\Leftrightarrow\)x(x-1)-6(x-1)=0

\(\Leftrightarrow\)(x-1)(x-6)=0

\(\Leftrightarrow\)\(\left[{}\begin{matrix}x-1=0\\x-6=0\end{matrix}\right.\)

\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=1\\x=6\end{matrix}\right.\)

Vậy S={1;6}