Question

(x+1)³ - x(x-2)² + x - 1 =0

Answer 1

https://i.imgur.com/NsVpNyK.jpg

Answer 2

(x+1)³-x(x-2)²+x-1=0

\(\Leftrightarrow\left(x^3+3x^2+3x+1\right)-x\left(x^2-4x+4\right)+x-1=0\)

\(\Leftrightarrow x^3+3x^2+3x+1-x^3+4x^2-4x+x-1=0\)

\(\Leftrightarrow7x^2=0\)

\(\Leftrightarrow x=0\)

Answer 3

( x + 1 )³ - x ( x - 2 )² + x - 1 = 0

<=> x³ + 3x² +3x + 1 - x ( x² - 4x + 4 ) - 1 = 0

<=> x³ + 3x² +3x + 1 - x³ + 4x² - 4x + x - 1 = 0

<=> 7x² = 0

<=> x² = 0

<=> x = 0
Vậy phương trình có nghiệm x = 0