Question

(x+1)\(^2\)=1

Answer 1

\(\left(x+1\right)^2=1\)

⇔ \(x+1=1\)

⇔ \(x=0\)

Answer 2

\(\left(x+1\right)^2=1\)

\(\Rightarrow\left[{}\begin{matrix}x+1=1\\x+1=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)

Answer 3

(x + 1)^2 = 1^2 = -1^2

+) x + 1 = 1

           x = 1 - 1

           x = 0

+ ) x+1 = -1

          x = -1 - 1 

          x = -2

vậy x = 0 ; -2

Answer 4

<=>X² +2x+1=1

<=> x² +2x=0

<=>x(x+2)=0

<=>x=0 hoac x=-2

Answer 5

Ta có: \(\left(x+1\right)^2=1\)

nên \(\left[{}\begin{matrix}x+1=1\\x+1=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)