\(\dfrac{x+1}{6}+\dfrac{x+8}{3}=\dfrac{x+1}{6}+\dfrac{2.\left(x+8\right)}{6}=\dfrac{3x+9}{6}\\ =\dfrac{3.\left(x+3\right)}{6}=\dfrac{x+3}{2}\)
\(\dfrac{x+1}{6}+\dfrac{x+8}{3}=\dfrac{x+1}{6}+\dfrac{2.\left(x+8\right)}{6}=\dfrac{3x+9}{6}\\ =\dfrac{3.\left(x+3\right)}{6}=\dfrac{x+3}{2}\)
x+1/6=x+8/3
giúp mk làm bài này với :>>>>
1/3 + 1/15 + 1/35 + ... + 1/9999
Giải ra thành các bước hộ mình với ạ, đây là bài tự luận.
Thanks <3
giải hộ mình bài này đi ạ....
4/x=x/9
Tìm x biết
a)\(\dfrac{11}{12}\).x + \(\dfrac{3}{4}\)= -\(\dfrac{1}{6}\)
b)3-\(\left(\dfrac{1}{6}-x\right)\).\(\dfrac{2}{3}\)=\(\dfrac{2}{3}\)
1/3 x 1/4 + 1/3 x 6/5 - 1/3
1/3 x 4/5 + 1/3 x 6/5 - 1/3
1+2+3+4+5+6+7+8+9+0+1+2+3+4+5+6+7+8+9+9+8+7+6+5+4+3+2+1+1+34+4+6+7+8+97+6+4+3+32+4+57+7+8+8+6+65+4+3+3+46+7+8+7+64+3+3+5+68+8+6+3+3+5+78+8+6+54+5+7+8+852+3+5+89+8+5+45+7×9×9×9×9×9×9×9×9×9×9×9×8×8×7×9×9×7×7×87×7×8×7×7×8×7×7×8
X/2018-1/70-1/15-1/21-...-1/120=5/8
(11/12+11/12.23+11/23.34+....+2/89.100)+x=5/3
(2'11.13+2/13.15+...+2/19.21)-x+4+221/231=7/3
-15/12 . x+ 3/7=6/5 .x -1/2