Question

(x-\(\dfrac{1}{3}\))³=\(\dfrac{-1}{8}\)

Answer 1

\(\left(x-\dfrac{1}{3}\right)^3=-\dfrac{1}{8}=\left(-\dfrac{1}{2}\right)^3\)

<=>\(x-\dfrac{1}{3}=\dfrac{1}{2}\)

<=>x=\(\dfrac{1}{2}+\dfrac{1}{3}\)

<=>x=\(\dfrac{5}{6}\)

Vậy S={\(\dfrac{5}{6}\)}

Answer 2

\(\left(x-\dfrac{1}{3}\right)^3=\dfrac{-1}{8}=\left(\dfrac{-1}{2}\right)^3\\ \Leftrightarrow x-\dfrac{1}{3}=\dfrac{-1}{2}\\ x=\dfrac{-1}{2}+\dfrac{1}{3}\\ x=\dfrac{-1}{6}\)