(x + \(\dfrac{1}{2}\) ) + (x + \(\dfrac{1}{8}\) ) + (x+\(\dfrac{1}{8}\))+(x+\(\dfrac{1}{16}\))=1
4x + \(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}\)=1
4x +\(\dfrac{15}{16}\)=1
4x = 1 -\(\dfrac{15}{16}\)
4x=\(\dfrac{1}{16}\)
x=\(\dfrac{1}{16}\div4\)
x=\(\dfrac{1}{64}\)