x - \(\dfrac{5x+2}{6}\)= \(\dfrac{7-3x}{4}\)⇔ \(\dfrac{24x-20x-8}{24}\)= \(\dfrac{42-18x}{24}\)
⇔24x-20x-8 = 42 - 18x ⇔ 22x = 50
⇒ x = \(\dfrac{50}{22}\) = \(\dfrac{25}{11}\)
\(\dfrac{x-\left(5x+2\right)}{6}=\dfrac{7-3x}{4}\)
hay
\(x-\dfrac{5x+2}{6}=\dfrac{7-3x}{4}\) ?