\(\sqrt{\left(x-5\right)^2}=4\\ \Leftrightarrow\left|x-5\right|=4\\ \Leftrightarrow\left[{}\begin{matrix}x-5=4\\x-5=-4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=9\\x=1\end{matrix}\right.\)
Vậy \(x\in\left\{9;1\right\}\)
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2
a.(x+5)(2x-1)=(2x-3)(x+1)
b.(x+1)(x+9)=(x+3)(x+5)
c.(3x+5)(2x+1)=(6x-2)(x-3)
d.(x-2)(3x+5)=(2x-4)(x+1)
đ.9x2 -1=(3x+1)(2x-3)
e.(2x+5)(x-4)=(x-5)(4-x)
1) \(\dfrac{5x-2}{3}\)= \(\dfrac{5-3x}{2}\)
2) \(\dfrac{x+4}{5}\) - x + 4 = \(\dfrac{x}{3}\) - \(\dfrac{x-2}{2}\)
3) \(\dfrac{10x+3}{12}\)= 1 + \(\dfrac{6+8x}{9}\)
4) \(\dfrac{x+1}{3}\)- \(\dfrac{x-2}{6}\) = \(\dfrac{2x-1}{2}\)
1) Phương trình dạng ax+b=0
1) 2x+x+12=0
2) x-5=3-x
3)2x-(3-5x)=4(x+3)
4)2x+3/3=5-4x/2
5) x-3/5=6- 1-2x/3
6) 3x-2/6 -5=3-2(x+7)/4
7) 3x-7/2+ x+1/3= -16
8) x- x+1/3=2x+1/5
bài 2 giải các phương trình sau
b,2(x+3)-4=0
d,5(x-3)=3x-5
f,7(5-x)=11-5x
h,2(3x-1)-3x=10
j,3-2x=3.(x+1)-x-2
m,4(2x-3)-5=6(3-x)-7
x2-4x+4=9
(x-7)(2x+5)=0
4x2-6x=0
4(3x-2)-3(x-4)=7x+10
2x(x+3)+5 (x+3)=0
2x (x-3)-5 ( x-3)=0
x3-6x2+5x=0
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
Giải phương trình về dạng ax + b = 0
1. (3x - 2)/3 - 2 = (4x + 1)/4
2. (x - 3)/4 + ( 2x - 1 )/3 = (2 - x)/6
3. 1/2 (x + 1) + 1/4(x + 3) = 3 - 1/3 (x + 2)
4 (x + 4)/5 - x + 4 = x/3 - (x - 2)/2
5. (4 - 5x)/6 = 2 (-x + 1)/2
Bài 1 : Giải các phương trình sau :
1) (x – 2)(x – 5) = (x – 3)(x – 4)
2) ( 6x + 2)(x – 2) = 2x(3x – 5)
3) (x – 2) 2 = (x – 3)(x + 2)
4) (x–1)(x +3) – (x+2)(x–3) = 0
5) (x–2)(x –5) – (x–3)(x–4) = 0
6) (3x – 2)(4x + 3) = 2x(6x – 1)
7) 4x 2 – (2x + 1)(2x – 1) = 0
8) (4x–5)(x+3) = (2x – 3)(7+2x)
9) (x + 3)(x – 2) = (x + 1) 2
10) (x+7)(x–7) + x 2 – 2 = 2(x 2 +5)
11) (x–1) 2 + (x+3) 2 = 2(x– 2)(x+2)
12) (x – 5) 2 = (x + 3) 2 + 2
13) (3x + 2) 2 – (3x – 2) 2 = 5x + 38
