a) \(\left(x-4\right)^2=9\)
\(\Leftrightarrow\left[\begin{matrix}x-4=3\\x-4=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
b) \(\left(2x-1\right)^3=8\)
\(\Leftrightarrow2x-1=\sqrt[3]{8}=2\)
\(\Leftrightarrow x=1,5\)
a/ (x - 4)2 = 9
=> (x - 4)2 = 32
hoặc (x - 4)2 = (-3)2
+) x - 4 = 3
=> x = 3 + 4 = 7
+) x - 4 = -3
=> x = -3 + 4 = 1
Vậy x = 7 hoặc x = -1
b/ (2x - 1)3 = 8
=> (2x - 1)3 = 23
=> 2x - 1 = 2
=> 2x = 2 + 1 = 3
=> x = \(\frac{3}{2}\)
Vậy x = \(\frac{3}{2}\)
1) \(\left(x-4\right)^2=9\)
=>\(\left[\begin{matrix}x-4=3\\x-4=-3\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=7\\x=1\end{matrix}\right.\)
Vậy....
2)\(\left(2x-1\right)^3=8\)
=> 2x-1=2
=>2x=3
=>x=3/2