`(x-3)6=4(x+2)`
`6x-18=4x+8`
`6x-4x=8+18`
`2x=26`
`x=13`
\(\left(x-3\right)\cdot6=4\cdot\left(x+2\right)\)
\(6x-18=4x+8\)
\(6x-4x=18+8\)
\(2x=26\)
\(x=\dfrac{26}{2}=13\)
Vậy \(x=13\)
\(\left(x-3\right).6=4.\left(x+2\right)\)
\(\Rightarrow6x-18=4x+8\)
\(\Rightarrow6x-4x=8+18\)
\(\Rightarrow2x=26\)
\(\Rightarrow x=13\)