\(x-3=5-x\)
\(\Rightarrow x+x=5+3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
Ta có: x - 3 = 5 - x
⇔ - 3 - 5 = - x - x
⇔ - 8 = - 2x
⇔ x = 4
\(x-3=5-x\)
\(\Rightarrow x+x=5+3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
Ta có: x - 3 = 5 - x
⇔ - 3 - 5 = - x - x
⇔ - 8 = - 2x
⇔ x = 4
tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
1.Tìm x, biết:
a) 7/8 + x = 4/7 b) 6 – x = (-3)/4 c) 1/(-5) + x = 3/4 d) –6 – x = (-3)/5
e) - 2/6 + x = 5/7 f) -8 – x = (-5)/3 g) - 2/10 – x = - 9/8 h) 8 – x = (-1)/6
i) - 2/5 + x = 5/7 j) -2 – x = (-5)/3 k) - 1/6 – x = - 9/8 l) 8 – x = (-1)/5
2. Tính:
a) -7/3 + 4/9 b) -8/18 - 15/56 c) (-7) - (-3/4) d) 0,15 + (-5/12)
e) -1/42 + -1/28 f) -1/21 + -1/36 g) 5,5 - (-2/7) h) 0,9 - (-4/7)
cho x=3.7 so sánh A= [x]+[x+1/5]+[x+2/5]+[x+3/5]+[x+4/5] và B=[5x]
a) -3/2 - 2x + 3/4 = 2
b) x/2 - (3x/5 - 13/5) = -(7/5 + 7/10 .x)
c) 2/3x - 3/12 = 4/5 - (7/x - x)
d) 3 - 2/2x-3 = 2/5 + 2/9-6x - 3/2
SẼ TICK NẾU XONG TỐI NAY
g) \(3-\dfrac{2}{2x-3}=\dfrac{2}{5}=\dfrac{2}{9-6x}-\dfrac{3}{2}\)
h) \(\dfrac{x}{2}-\dfrac{1}{x}=\dfrac{1}{12}\)
i) \(x^2-\dfrac{7}{6}x+\dfrac{1}{3}=0\)
k) \(\dfrac{13}{x-1}+\dfrac{5}{2x-2}-\dfrac{6}{3x-3}\)
m) \(\left(\dfrac{3}{2}-\dfrac{2}{-5}\right):x-\dfrac{1}{2}=\dfrac{3}{2}\)
n) \(\left(\dfrac{3}{2}-\dfrac{5}{11}-\dfrac{3}{13}\right)\left(2x-2\right)=\left(-\dfrac{3}{4}+\dfrac{5}{22}+\dfrac{3}{26}\right)\)
1.Tìm x
a) \(1\dfrac{4}{5}=-0,15-x\)
b) \(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
c) \(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)
Bài 7 :
a. x - 2/35 = -2/25 . b.11/12 - ( x + 2/5 ) = 2/3 .
c. 2/5 + 1/4 . x = -3/10 .
tim x
\(\dfrac{5}{6}x-\dfrac{3}{4}=\dfrac{-1}{4}+\dfrac{2}{3}\)
\(-1\dfrac{1}{2}-\dfrac{2}{3}x=\dfrac{5}{6}-\left(\dfrac{-2}{5}\right)\)
\(\left(\dfrac{4}{5}:x+1,5\right):\dfrac{2}{3}=-1,5\)
\(\dfrac{4}{3}x-\dfrac{2}{3}=\dfrac{1}{4}-x\)
giup minh nhe minh dang can gap
X + 5/6 = 3/5 - x
Tìm x biết :
a) \(\dfrac{x+2}{327}+\dfrac{x+3}{326}+\dfrac{x+4}{325}+\dfrac{x+5}{324}+\dfrac{x+349}{5}=0\)
b) \(|5x-3|\ge7\)