Question

(x-3)^2+(-17)=32

Answer 1

\(\left(x-3\right)^2+\left(-17\right)=32\)

`(x-3)^2 - 17 =32`

`(x-3)^2 = 32 + 17`

`(x-3)^2 = 49`

`(x-3)^2 = 7^2`

`=>`\(\left[{}\begin{matrix}x-3=7\\x-3=-7\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=7+3\\x=-7+3\end{matrix}\right.\)

`=>` \(\left[{}\begin{matrix}x=10\\x=-4\end{matrix}\right.\)

Vậy....

`#LeMichael`

Answer 2

\(\left(x-3\right)^2=32+17\\ \left(x-3\right)^2=49\\ TH1\left(x-3\right)^2=7^2\\ x-3=7\\ x=7+3\\ x=10\\ TH2\left(x-3\right)^2=\left(-7\right)^2\\ x-3=-7\\ x=-7+3\\ x=-4\)