\(\left|x-2\right|=x\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=x\\x-2=-x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-x=2\\x+x=2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x\in\varnothing\\2x=2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x\in\varnothing\\x=1\end{matrix}\right.\)
Vậy \(x=1\)
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