\(\left(x-2\right)\left(3-4x\right)=x^2-4x+4\)
\(\Leftrightarrow\left(x-2\right)\left(3-4x\right)-\left(x-2\right)^2=0\)
\(\Leftrightarrow\left(x-2\right)\left(3-4x-x+2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(5-5x\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\\\5-5x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\\\x=1\end{matrix}\right.\)
Vậy, \(S=\left\{1;2\right\}\)