\(\left|x-2\right|+1=5\Leftrightarrow\left|x-2\right|=4\Leftrightarrow\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)
|x-2|+1=5
⇒|x-2|=4
⇒\(\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)
Vậy x∈\(\left\{-2,6\right\}\)
\(\left|x-2\right|\) + 1 = 5
\(\left|x-2\right|\) = 5 - 1
\(\left|x-2\right|\) = 4
=> x - 2 ∈ { -4 ; 4 }
=> x ∈ { -2 ; 6 }
|x-2|+1=5
\(\Leftrightarrow\) |x-2|= 5-1
\(\Leftrightarrow\) |x-2|=4
\(\Rightarrow\) x-2=4 hoặc x-2=-4
\(\Leftrightarrow\) x-2=4 \(\Leftrightarrow\) x-2=-4
\(\Leftrightarrow\) x = 4+2 \(\Leftrightarrow\) x =-4+2
\(\Leftrightarrow\) x = 6. \(\Leftrightarrow\) x = -2.
Vậy x \(\in\) \(\left\{6;-2\right\}\)