\(\left(x+1,5-\dfrac{3}{7}\right):\dfrac{1}{2}=1\dfrac{1}{7}\)
=> \(\left(x+\dfrac{3}{2}-\dfrac{3}{7}\right).2=\dfrac{8}{7}\)
=> \(x+\dfrac{3}{2}-\dfrac{3}{7}=\dfrac{8}{7}.\dfrac{1}{2}\)
=> \(x+\dfrac{21}{14}-\dfrac{6}{14}=\dfrac{8}{14}\)
=> x=\(\dfrac{8}{14}+\dfrac{6}{14}-\dfrac{21}{14}\)
=> x=\(\dfrac{-7}{14}=-\dfrac{1}{2}\)
vậy x=-\(\dfrac{1}{2}\)