Question

Answer 1

\(\left[\left(x+\dfrac{1}{3}\right)+\dfrac{1}{6}\right]-\dfrac{1}{2}:2=\dfrac{3}{4}\)

\(\Rightarrow\left(x+\dfrac{1}{3}+\dfrac{1}{6}\right)-\dfrac{1}{4}=\dfrac{3}{4}\)

\(\Rightarrow x+\dfrac{1}{2}=\dfrac{3}{4}+\dfrac{1}{4}=1\)

\(\Rightarrow x=1-\dfrac{1}{2}=\dfrac{1}{2}\)

Vậy......

Answer 2

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