(x-1)2=25
=> (x-1)2=52
=> x-1=5
=> x=5+1
=> x= 6
Vậy x= 6
\(\left(x-1\right)^2=25\)
\(\Rightarrow x-1=\pm5\)
+) \(x-1=5\Rightarrow x=6\)
+) \(x-1=-5\Rightarrow x=-4\)
Vậy \(x\in\left\{6;-4\right\}\)
(x-1)\(^2\)=25
(x-1)\(^2\)=5\(^2\)
x-1=5
x=5+1
x=6
(x-1)\(^2\)=25
\(\Rightarrow\)x-1=+5
+)x-1=5\(\Rightarrow\)x=6
+)x-1=-5\(\Rightarrow\)x=-4
vậy x\(\in\){6;-4}