Question

(x - 12) (x + 3) = 0

Answer 1

\(\left(x-12\right)\left(x+3\right)=0\\ \)

\(\Rightarrow\begin{cases}x-12=0\\x+3=0\end{cases}\Rightarrow\begin{cases}x=12\\x=-3\end{cases}\)

Answer 2

\(\left(x-12\right)\left(x+3\right)=0\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=0+12\\x=0-3\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=12\\x=-3\end{array}\right.\)

Answer 3

(x - 12) (x+3)=0

x=0+12   x=0-3

x=12        x=-3