( x - 12 ).( x + 3 ) = 0
\(\Rightarrow x-12=0\) hoặc \(x+3=0\)
+) \(x-12=0\Rightarrow x=12\)
+) \(x+3=0\Rightarrow x=-3\)
Vậy x = 12 hoặc x = -3
\(\left(x-12\right)\left(x+3\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-12=0\\x+3=0\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=12\\x=-3\end{array}\right.\)
Vậy x=12 ; x = - 3
(x-12)x(x+3)
Suy ra x-12=0;x=0;x+3=0
x-12=0
x=-12
x+3=0
x=-3
Vậy x=-12;x=0;x=-3
( x - 12 ).( x + 3 ) = 0
⇒x−12=0⇒x−12=0 hoặc x+3=0x+3=0
+) x−12=0⇒x=12x−12=0⇒x=12
+) x+3=0⇒x=−3x+3=0⇒x=−3
Vậy x = 12 hoặc x = -3
(x-12).(x+3) = 0
⇒ x-12=0 hoặc x+3=0
Nếu :
x-12=0
x = 0+12
x = 12
Nếu :
x+3 = 0
x = 0-3
x = -3
Vậy x ∈ {-3; 12}