%27Al=\(\dfrac{23.100}{23+2}=92\%\)
%29Al=8%
\(\overline{M_{Al}}=\dfrac{92.27+8.29}{100}\approx27,16\)
Trong Al2X3 ta có:
%27Al=\(\dfrac{2.27,16.\dfrac{92}{100}}{2.27,16+3X}.100=33,05\)
54,32+3X=151,21\(\rightarrow\)3X=96,89\(\rightarrow\)X=32,3