\(2M+2H_2O\rightarrow2MOH+H_2\\ M_2O+H_2O\rightarrow2MOH\\ Đặt:n_M=a\left(mol\right);n_{M_2O}=b\left(mol\right)\\ MOH+HCl\rightarrow MCl+H_2O\\ n_{HCl}=0,2.0,35=0,07\left(mol\right)\\ \Rightarrow n_{MOH}=0,07\left(mol\right)\\ \Rightarrow\left\{{}\begin{matrix}a.M_M+b.\left(2M_M+16\right)=1,93\\0,5a=0,015\\a+2b=0,07\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=0,03\\b=0,02\\M_M=23\left(\dfrac{g}{mol}\right)\end{matrix}\right.\\ \Rightarrow M\left(I\right):Natri\left(Na=23\right)\)
=>Chọn B
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