a) \(\frac{{4 + 3\sqrt 5 }}{{\sqrt 5 }} = \frac{{\left( {4 + 3\sqrt 5 } \right)\sqrt 5 }}{{\sqrt 5 .\sqrt 5 }} = \frac{{4\sqrt 5 + 15}}{5}\)
b) \(\frac{1}{{\sqrt 5 - 2}} = \frac{{1.\left( {\sqrt 5 + 2} \right)}}{{\left( {\sqrt 5 - 2} \right)\left( {\sqrt 5 + 2} \right)}} = \frac{{\sqrt 5 + 2}}{{5 - 4}} = \sqrt 5 + 2\)
c) \(\frac{{3 + \sqrt 3 }}{{1 - \sqrt 3 }}\)\( = \frac{{\left( {3 + \sqrt 3 } \right)\left( {1 + \sqrt 3 } \right)}}{{\left( {1 - \sqrt 3 } \right)\left( {1 + \sqrt 3 } \right)}}\)\( = \frac{{3 + 3\sqrt 3 + \sqrt 3 + \sqrt {{3^2}} }}{{1 - 3}}\)\( = \frac{{6 + 4\sqrt 3 }}{{ - 2}}\)\( = -3-2\sqrt 3 \)
d) \(\frac{{\sqrt 2 }}{{\sqrt 3 + \sqrt 2 }} = \frac{{\sqrt 2 \left( {\sqrt 3 - \sqrt 2 } \right)}}{{\left( {\sqrt 3 + \sqrt 2 } \right)\left( {\sqrt 3 - \sqrt 2 } \right)}} = \frac{{\sqrt 6 - 2}}{{3 - 2}} = \sqrt 6 - 2\)