Khoang cach giua 5 van sang lien tiep la 2 mm
=> \(i=\dfrac{2}{4}=0,5\left(mm\right)\)
\(i=\dfrac{\lambda.D}{a}\Leftrightarrow\lambda=\dfrac{i.a}{D}=\dfrac{0,5.2}{1,6}=0,625\mu m\)
\(x=\dfrac{k.\lambda.D}{a}\Leftrightarrow2.\dfrac{5.\lambda.1,6}{2}\Rightarrow\lambda=0,5\mu m\)