Với 200g dd H2SO4 9.8% ==> mH2SO4 = 200x9.8/100 = 19.6 (g)
Với 300g dd H2SO4 19.6% => mH2SO4 = 300x19.6/100 = 58.8 (g)
mdd H2SO4 = 200 + 300 = 500 (g)
C% X = (19.6+58.8)x100/500 = 15.68%
mH2SO4 = 19.6 + 58.8 = 78.4 (g)
===> nH2SO4 = m/M = 78.4/98 = 0.8 (mol)
H2SO4 + 2KOH => K2SO4 + 2H2O
==> nKOH = 0.8 x 2 = 1.6 (mol)
V = n/CM = 1.6/1 = 1.6 (l) = 1600ml