a) \(\overrightarrow {AB} = (4;6;8) \Rightarrow AB = \sqrt {{4^2} + {6^2} + {8^2}} = 2\sqrt {29} \)
\(\overrightarrow {AC} = (8;10;3) \Rightarrow \sqrt {{8^2} + {{10}^2} + {3^2}} = \sqrt {173} \)
\(\overrightarrow {BC} = (4;4; - 5) \Rightarrow \sqrt {{4^2} + {4^2} + {{( - 5)}^2}} = \sqrt {57} \)
c) \(\cos \widehat {BAC} = \frac{{\overrightarrow {AB} .\overrightarrow {AC} }}{{|\overrightarrow {AB} |.|\overrightarrow {AC} |}} = \frac{{4.8 + 6.10 + 8.3}}{{2\sqrt {29} .\sqrt {173} }} \approx 0,82 \Rightarrow \widehat {BAC} = 35,03^\circ \)
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