Đặt \(A=2^0+2^1+...+2^{10}\)
\(\Leftrightarrow2A=2^2+2^3+...+2^{11}\\ \Leftrightarrow A=2^{11}-2^0=2^{11}-1\)
S = 1 + 2 + 22 + ... + 29 + 210
2S = 2 . (2 + 22 + ... + 29 + 210)
2S = 2 + 22 + 23 + ... + 210 + 211
2S - S = (2 + 22 + 23 + ... + 210 + 211 ) - (1 + 2 + 22 + ... + 29 + 210)
S = 211 - 1
Đặt A = 20+21+...+210
=>2A = 22+23+...+211
=>A= 211 − 20 = 211 − 1
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