Question

Tính:

a) \(\text{889972 + 96308}\);                               b) \(\dfrac{5}{6}+\dfrac{7}{12}\);

c) \(3+\dfrac{5}{7}\)                                               d) \(926,83+549,67\).

Answer 1

a) 889972 + 96308 = 986280

b) \(\dfrac{5}{6}+\dfrac{7}{12}=\dfrac{10}{12}+\dfrac{7}{12}=\dfrac{17}{12}\)

c) \(3+\dfrac{5}{7}=\dfrac{21}{7}+\dfrac{5}{7}=\dfrac{26}{7}\)

d) 926,83 + 549,67 = 1476,5

Answer 2

a)889972 + 96308=986280

c)3+5/7=21/7+5/7=26/7

b)5/6+7/12=10/12+7/12=17/12

d)926,83+549,67=1476,5

Answer 3

a) 889972 + 96308=986280

b) \(\dfrac{5}{6}\)+\(\dfrac{7}{12}\)=\(\dfrac{10}{12}\)+\(\dfrac{7}{12}\)=\(\dfrac{17}{12}\)

c) 3+\(\dfrac{5}{7}\)=\(\dfrac{21}{7}\)+\(\dfrac{5}{7}\)=\(\dfrac{26}{7}\)

d) 926,83 +549,67=1476,5