Question

Tính.

a) $\frac{1}{3} + \frac{1}{3} + \frac{1}{6}$         

b) $\frac{1}{{12}} + \frac{3}{4} + \frac{2}{{12}}$

c) $\frac{{19}}{{15}} + 0 + \frac{{11}}{{15}}$

Answer 1

a) $\frac{1}{3} + \frac{1}{3} + \frac{1}{6} = \frac{2}{3} + \frac{1}{6} = \frac{4}{6} + \frac{1}{6} = \frac{5}{6}$   

b) $\frac{1}{{12}} + \frac{3}{4} + \frac{2}{{12}} = \left( {\frac{1}{{12}} + \frac{2}{{12}}} \right) + \frac{3}{4} = \frac{1}{4} + \frac{3}{4} = \frac{4}{4} = 1$

c) $\frac{{19}}{{15}} + 0 + \frac{{11}}{{15}} = \frac{{19 + 11}}{{15}} = \frac{{30}}{{15}} = 2$