Question

Tính xem A gấp mấy lần B :

a ) A = 3,4 . 10^-8 ; B = 3,4 x 10^-9

b ) A = 10^-4 + 10^-3 + 10^-2 , B = 10^-9

Answer 1

a: \(\dfrac{A}{B}=\dfrac{3.4\cdot10^{-8}}{3.4\cdot10^{-9}}=\dfrac{1}{10^8}:\dfrac{1}{10^9}=10\)

=>A gấp 10 lần B

b: \(\dfrac{A}{B}=\dfrac{10^{-4}+10^{-3}+10^{-2}}{10^{-9}}=\dfrac{10^{-2}\cdot\left(10^{-2}+10^{-1}+1\right)}{10^{-9}}=\dfrac{1}{10^7}\cdot\dfrac{111}{100}=\dfrac{111}{10^9}\)

=>A bằng 111/10⁹ lần B