\(\left(1+\dfrac{1}{1.3}\right).\left(1+\dfrac{1}{2.4}\right).\left(1+\dfrac{1}{3.5}\right)......\left(1+\dfrac{1}{2009.2011}\right)\)
\(=\dfrac{4}{1.3}.\dfrac{9}{2.4}.\dfrac{16}{3.5}........\dfrac{4040100}{2009.2011}\)
\(=\dfrac{2.2.3.3.4.4.....................2010.2010}{1.3.2.4.3.5.................2008.2010.2009.2011}\)
\(=\dfrac{2.2010}{2011}\)
không biết đúng k nhưng cứ lm thôi
Tính:\(\dfrac{1}{1.3}\) +\(\dfrac{1}{3.5}\) +\(\dfrac{1}{5.7}\) +.....+\(\dfrac{1}{2009.2011}\)
tính
S=\(\dfrac{1}{1.3}-\dfrac{1}{2.4}+\dfrac{1}{3.5}-\dfrac{1}{4.6}+\dfrac{1}{5.7}-\dfrac{1}{6.8}+\dfrac{1}{7.9}-\dfrac{1}{8.10}\)
ai biết giúp mk nha ...thanks nhìu....đúng mk tik
Tính A = \(\left(1+\dfrac{1}{1.3}\right)\left(1+\dfrac{1}{2.4}\right)\left(1+\dfrac{1}{3.5}\right)....\left(1+\dfrac{1}{99.101}\right)\)
Tinh nhanh : 
Help me !!!
A= \(\dfrac{1}{1.3}\) + \(\dfrac{1}{3.5}\) + \(\dfrac{1}{5.7}\) + ... + \(\dfrac{1}{2009.2011}\)
1.tìm x
a) (\(\dfrac{2}{11.13}+\dfrac{2}{13.15}+...+\dfrac{2}{19.21}).462-[2,04:(x+1,05)]:0,12=19\)
b) \(\dfrac{1}{24.25}+\dfrac{1}{25.26}+...+\dfrac{1}{29.30}+x:\dfrac{1}{3}=-4\)
2. thực hiện phép tính
a)\(\dfrac{15}{28}-\dfrac{186}{116}-\dfrac{121}{462}+\dfrac{189}{198}\)
b)\((1+\dfrac{1}{1.3}).(1+\dfrac{1}{2.4}).(1+\dfrac{1}{3.5})...(1+\dfrac{1}{99.100})\)
Tính nhanh:
\(M=\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{995.997}+\dfrac{1}{997.999}\)
tìm x:
a,\(\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{9.10}\right).\left(x-1\right)+\dfrac{1}{10}.x=x-\dfrac{9}{10}\)
b,\(\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{97.99}\right).\left(x-2\right)+x=\dfrac{149}{99}.x-\dfrac{98}{99}\)
Cho A=\(2.\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+...+\dfrac{1}{2015.2017}\right)\)
B=\(\dfrac{2013.2015.2017}{2018.2013.\left(2014+1\right)}\)
a/Tính Avà B
b/So sánh A và B
Tìm x:
a)\(2016x+\left(\dfrac{7}{12}+\dfrac{4}{21}+\dfrac{2}{24}+\dfrac{11}{30}+\dfrac{3}{40}+\dfrac{15}{56}\right)-\left(\dfrac{2}{3}+\dfrac{2}{4}+\dfrac{2}{5}\right)=0\)
b\(\dfrac{2x-1}{x+2015}-\dfrac{4025}{x+2017}=\dfrac{x-2014}{2x-4036}-\dfrac{x-2013}{2x-4030}\) (x thuộc N)
c)\(\left(1+\dfrac{1}{1.3}\right)\left(1+\dfrac{1}{2.4}\right)\left(1+\dfrac{1}{3.5}\right)...\left(1+\dfrac{1}{x\left(x+2\right)}\right)=\dfrac{4016}{2007}\)
AI GIÚP MK VỚI MK TICK CHO 
