\(n_A=\dfrac{2,8}{22,4}=0,125\left(mol\right)\)
\(M_A=1,1724.29\approx34\)
CTHH của A: HxSy
\(M_S=\dfrac{94,12.34}{100}\approx32\Rightarrow x=1\)
\(M_H=34-32=2\Rightarrow y=2\)
CT: H2S
2H2S + 3O2 \(\underrightarrow{t^o}\) 2SO2 + 2H2O
de: 0,125\(\rightarrow\)0,1875
\(V_{O_2}=22,4.0,1875=4,2l\)