\(\left(-C_6H_{10}O_5-\right)_n\left(\dfrac{1}{162n}\right)+nH_2O\xrightarrow[Axit]{t^o}nC_6H_{12}O_6\left(\dfrac{1}{162}\right)\)
\(n_{\left(-C_6H_{1O}O_5-\right)_n}=\dfrac{1}{162n}\)(tấn mol)
\(\Rightarrow n_{C_6H_{12}O_6}=\dfrac{1}{162}\)(tấn mol)
\(C_6H_{12}O_6\xrightarrow[30-35^oC]{lên-men-rươu}2C_2H_5OH+2CO_2\)
Vì H=75%
\(\Rightarrow n_{C_2H_5OH}=\dfrac{1}{162}.2.\dfrac{75}{100}=\dfrac{1}{108}\)(tấn mol)
\(\Rightarrow m_{C_2H_5OH}=\dfrac{1}{108}.46=\dfrac{23}{54}\)(tấn)\(=425925,9259\left(g\right)\)
\(\Rightarrow V_{ddC_2H_5OH}=\dfrac{425925,9259}{0,8.1000}=532,407\left(l\right)\)
C6H10O5 \(\rightarrow\) 2C2H5OH + 2CO2
162 2* 46
\(10^6\) \(\rightarrow\) \(m_{ddC2H5OH}\)= \(\dfrac{10^6.2.46.75}{162.100}\)=425925,9259
\(V_{C2H5OH}\)=\(\dfrac{m_{ddC2H5Oh}}{d}\)=532407,4074 ml
