Question

tính thành phần trăm theo khối lượng các nguyên tố trong các hợp chất sau:

a,p₂o₅

b,Na₂SO₄

c,Mg(NO₃)₄

_d,Fe(SO4)3

_h,Ae(NO3)3

 

Answer 1

a. M_P2O5=31.2+16.5=142 (g)

%m_P=\(\frac{31.2}{142}.100\%\approx43,7\%\)

%m_O=\(\frac{16.5}{142}.100\%\approx56,3\%\)

b. M_Na2SO4=23.2+32+16.4=142 (g)

\(\%m_{Na}=\frac{23.2}{142}.100\%\approx32,4\%\)

\(\%m_S=\frac{32}{142}.100\%\approx22,5\%\)

\(\%m_O=\frac{16.4}{142}.100\%\approx45,1\%\)

Answer 2

c. M_Mg(NO3)4=24+4(14+16.3)=272(g)

\(\%m_{Mg}=\frac{24}{272}.100\%\approx8,8\%\)

\(\%m_N=\frac{14.4}{272}.100\%\approx20,6\%\)

\(\%m_O=\frac{16.3.4}{272}.100\%\approx70,6\%\)

Answer 3

d. M_Fe(SO4)3=56+3(32+16.4)=344(g)

\(\%m_{Fe}=\frac{56}{344}.100\%\approx16,3\%\)

\(\%m_S=\frac{32.3}{344}.100\%\approx27,9\%\)

\(\%m_O=\frac{16.4.3}{344}.100\%\approx55,8\%\)

Answer 4

e. Ae là nguyên tố j vậy pn