\(=\sqrt{15-2\sqrt{15.12}+12}=\sqrt{\left(\sqrt{15}-\sqrt{12}\right)^2}\)
\(=\left|\sqrt{15}-\sqrt{12}\right|=\sqrt{15}-2\sqrt{3}\)
\(=\sqrt{15-2\sqrt{15.12}+12}=\sqrt{\left(\sqrt{15}-\sqrt{12}\right)^2}\)
\(=\left|\sqrt{15}-\sqrt{12}\right|=\sqrt{15}-2\sqrt{3}\)
1)\(\sqrt{12}\)\(-\)\(\sqrt{27}\)\(+\)\(\sqrt{48}\)
2)(\(\sqrt{24}+\sqrt{20}-\sqrt{80}\))\(\div\)5
3)2\(\sqrt{27}-\sqrt{\dfrac{16}{3}}\)\(-\)\(\sqrt{48}-\)\(\sqrt{8\dfrac{1}{3}}\)
4) \(\dfrac{1}{\sqrt{5}-\sqrt{3}}\)\(-\)\(\dfrac{1}{\sqrt{5+\sqrt{3}}}\)
Thực hiện phép tính: \(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\)
\(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}+\sqrt{162}}\)
\(\sqrt{27-12\sqrt{ }5}\)
thực hiện phép tính
\(\dfrac{2\sqrt{8}-\sqrt{12}}{\sqrt{18}-\sqrt{48}}-\dfrac{\sqrt{5}+\sqrt{27}}{\sqrt{30}-\sqrt{162}}\)
Rút gọn
A=\(3\sqrt{3}-2\sqrt{12}-27\)
B= \(\sqrt{\left(3-\sqrt{5}\right)^2}+\sqrt{6-2\sqrt{5}}\)
\(\sqrt{\left(\sqrt{3}-2\right)^2}+\sqrt{12}\)
\(2\sqrt{27}-6\sqrt{\frac{4}{3}}+\frac{3}{5}\sqrt{75}\)
\(3\sqrt{12}-4\sqrt{27}+5\sqrt{48}\)
\(\left(\sqrt{45}-2\sqrt{10}+\sqrt{5}\right)\sqrt{5}+5\sqrt{8}\)
Tính giúp mình nhé mình cần gấp
Thực hiện phép tính:
a,\(\frac{1}{2}\sqrt{48}-5\sqrt{27}+2\sqrt{147}-\sqrt{108}\)
b,\(\sqrt{\left(\sqrt{5}-3\right)^2}+\sqrt{\left(1+\sqrt{5}\right)^2}\)
c,\(\frac{12}{3+\sqrt{3}}-\frac{6}{\sqrt{3}}+\frac{\sqrt{27}-3\sqrt{2}}{\sqrt{3}-\sqrt{2}}\)
d,\(\left(\sqrt{2+\sqrt{3}}-\sqrt{3+\sqrt{5}}\right)^2\)
Giúp mk vs huhu mk hứa sẽ tick ạ :>