\(n_C=\dfrac{96}{12}=8\left(mol\right)\\ n_S=\dfrac{96}{32}=3\left(mol\right)\\ PTHH:C+O_2-to->CO_2\\ S+O_2-to->SO_2\\ n_{O_2}=8+3=11\left(mol\right)\\ =>m_{O_2}=11.32=352\left(g\right)\)
nC=96/12=8(mol)
nS=96/32=3(mol)
pt: C+O2=>CO2
Theo pt: nO2=nC=8(mol)
S+O2=>SO2
Theo pt: nO2=nS=3(mol)
\(\Sigma nO2=8+3=11\left(mol\right)\)
=>mO2=11.32=352(g)