Gọi 2a là số mol Na cần thiết
=>mNa=23.2a=46a
2Na+2H2O->2NaOH+H2
2a......................2a........a...(mol)
Theo PTHH:mNaOH=40.2a=80a
\(m_{H_2}\)=2a
Ta có:mdd(sau)=500+46a-2a=500+44a
Theo gt:C%dd=20%
=>\(\dfrac{80a}{500+44a}\).100%=20%
=>8000a=10000+880a=>7120a=10000
=>a=1,4(mol)
Vậy mNa=46a=1,4.46=64,4(g)