Question

Tính số % các nguyên tố:

MgSO₄; Ca(OH)₂; NaHCO₃; K₂SO₃

Answer 1

+ MgSO₄ = 120

\(\%Mg=\dfrac{24}{120}.100\%=20\%\)

\(\%S=\dfrac{32}{120}.100\%\approx26,67\%\)

\(\%O=100-\left(20+26,67\right)\approx53,33\%\)

+ Ca(OH)₂ = 74

\(\%Ca=\dfrac{40}{74}.100\%\approx54,05\%\)

\(\%O=\dfrac{32}{74}.100\%\approx43,24\%\)

\(\%H\approx2,71\%\)

+ NaHCO₃ = 84

\(\%Na=\dfrac{23}{84}.100\%\approx27,38\%\)

\(\%H=\dfrac{1}{84}.100\%\approx1,19\%\)

\(\%C=\dfrac{12}{84}.100\%\approx14,29\%\)

\(\%O\approx57,14\%\)

+ K₂SO₃ = 158

\(\%K=\dfrac{78}{158}.100\%\approx49,37\%\)

\(\%S=\dfrac{32}{158}.100\%\approx20,25\%\)

\(\%O\approx30,38\%\)