a, Al(OH)3 = 78
\(\%Al=\dfrac{27}{78}.100\%\approx34,62\%\)
\(\%O=\dfrac{48}{78}.100\%\approx61,54\%\)
\(\%H=100-\left(61,54+34,62\right)\approx3,84\%\)
b, (NH2)2 CO = 60
\(\%N=\dfrac{28}{60}.100\%\approx46,67\%\)
\(\%H=\dfrac{4}{60}.100\%\approx6,67\%\)
\(\%C=\dfrac{12}{60}.100\%=20\%\)
\(\%O=100-\left(20+6,67+46,67\right)\approx26,66\%\)