\(\frac{7}{13}.\frac{7}{15}-\frac{5}{12}.\frac{21}{39}+\frac{49}{91}.\frac{8}{15}\\ =\frac{7}{13}.\frac{7}{15}-\frac{5}{12}.\frac{7}{13}+\frac{7}{13}.\frac{8}{15}\\ =\frac{7}{13}\left(\frac{7}{15}+\frac{8}{15}-\frac{5}{12}\right)\\ =\frac{7}{13}\left(1-\frac{5}{12}\right)\\ =\frac{7}{13}.\frac{7}{12}\\ =\frac{49}{156}\)